Random Formulas

Inverse a Number

Mod(%) operation on a number by 10 returns the rightmost digit Divide(/) operation on a number by 10 removes the rightmost digit

Num = 126

$Num=(1\ast 100)+(2\ast 10)+(6)$

Reversing 126 % 10 = 6
int(126/10) = 12
12 % 10 = 2
int(12/10) = 1
1 % 10 = 1

$Reverse=(6\ast 100)+(2\ast 10)+(1)$